What is the integral of ((3x-2)^2)/(sqrt(x)) ?

The integral of ((3x-2)^2)/(sqrt(x)) is 18/5 x^{5/2}-8x^{3/2}+8sqrt(x)+C

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integral of ((3x-2)^2)/(sqrt(x))

\int \frac{( 3 x - 2 ) ^{2}}{x} d x

\frac{18}{5} x^{\frac{5}{2}} - 8 x^{\frac{3}{2}} + 8 x + C

Solution steps

\int \frac{( 3 x - 2 ) ^{2}}{x} d x

Expand

\frac{( 3 x - 2 ) ^{2}}{x} : 9 x^{\frac{3}{2}} - 12 x + \frac{4}{x}

= \int 9 x^{\frac{3}{2}} - 12 x + \frac{4}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 x^{\frac{3}{2}} d x - \int 12 x d x + \int \frac{4}{x} d x

\int 9 x^{\frac{3}{2}} d x = \frac{18}{5} x^{\frac{5}{2}}

\int 12 x d x = 8 x^{\frac{3}{2}}

\int \frac{4}{x} d x = 8 x

= \frac{18}{5} x^{\frac{5}{2}} - 8 x^{\frac{3}{2}} + 8 x

Add a constant to the solution

= \frac{18}{5} x^{\frac{5}{2}} - 8 x^{\frac{3}{2}} + 8 x + C

What is the integral of ((3x-2)^2)/(sqrt(x)) ?
The integral of ((3x-2)^2)/(sqrt(x)) is 18/5 x^{5/2}-8x^{3/2}+8sqrt(x)+C