What is the integral of (3x-5)/(sqrt(1-x^2)) ?

The integral of (3x-5)/(sqrt(1-x^2)) is -3sqrt(1-x^2)-5arcsin(x)+C

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integral of (3x-5)/(sqrt(1-x^2))

\int \frac{3 x - 5}{1 - x ^{2}} d x

- 3 1 - x^{2} - 5 arcsin (x) + C

Solution steps

\int \frac{3 x - 5}{1 - x ^{2}} d x

Expand

\frac{3 x - 5}{1 - x ^{2}} : \frac{3 x}{1 - x ^{2}} - \frac{5}{1 - x ^{2}}

= \int \frac{3 x}{1 - x ^{2}} - \frac{5}{1 - x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3 x}{1 - x ^{2}} d x - \int \frac{5}{1 - x ^{2}} d x

\int \frac{3 x}{1 - x ^{2}} d x = - 3 1 - x^{2}

\int \frac{5}{1 - x ^{2}} d x = 5 arcsin (x)

= - 3 1 - x^{2} - 5 arcsin (x)

Add a constant to the solution

= - 3 1 - x^{2} - 5 arcsin (x) + C

What is the integral of (3x-5)/(sqrt(1-x^2)) ?
The integral of (3x-5)/(sqrt(1-x^2)) is -3sqrt(1-x^2)-5arcsin(x)+C