What is the integral of e^{-z} ?

The integral of e^{-z} is -e^{-z}+C

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integral of e^{-z}

\int e^{- z} d z

- e^{- z} + C

Solution steps

\int e^{- z} d z

Apply u-substitution

= \int - e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - e^{u}

Substitute back

u = - z

= - e^{- z}

Add a constant to the solution

= - e^{- z} + C