What is the integral of 10e^{2x} ?

The integral of 10e^{2x} is 5e^{2x}+C

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integral of 10e^{2x}

\int 10 e^{2 x} d x

5 e^{2 x} + C

Solution steps

\int 10 e^{2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int e^{2 x} d x

Apply u-substitution

= 10 \cdot \int e^{u} \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \frac{1}{2} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 10 \cdot \frac{1}{2} e^{u}

Substitute back

u = 2 x

= 10 \cdot \frac{1}{2} e^{2 x}

Simplify

10 \cdot \frac{1}{2} e^{2 x} : 5 e^{2 x}

= 5 e^{2 x}

Add a constant to the solution

= 5 e^{2 x} + C