What is the integral of 1/((2-3x)^2) ?

The integral of 1/((2-3x)^2) is 1/(3(2-3x))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 1/((2-3x)^2)

\int \frac{1}{( 2 - 3 x ) ^{2}} d x

\frac{1}{3 ( 2 - 3 x )} + C

Solution steps

\int \frac{1}{( 2 - 3 x ) ^{2}} d x

Apply u-substitution

= \int - \frac{1}{3 u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{3} \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

= - \frac{1}{3} (- \frac{1}{u})

Substitute back

u = 2 - 3 x

= - \frac{1}{3} (- \frac{1}{2 - 3 x})

Simplify

- \frac{1}{3} (- \frac{1}{2 - 3 x}) : \frac{1}{3 ( 2 - 3 x )}

= \frac{1}{3 ( 2 - 3 x )}

Add a constant to the solution

= \frac{1}{3 ( 2 - 3 x )} + C

What is the integral of 1/((2-3x)^2) ?
The integral of 1/((2-3x)^2) is 1/(3(2-3x))+C