What is the integral of (tan(x))/(1-tan^2(x)) ?

The integral of (tan(x))/(1-tan^2(x)) is xcos(x)sin(x)sec(2x)-1/2 xtan(2x)-1/4 ln|cos(2x)|+C

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integral of (tan(x))/(1-tan^2(x))

\int \frac{tan ( x )}{1 - tan ^{2} ( x )} d x

x cos (x) sin (x) sec (2 x) - \frac{1}{2} x tan (2 x) - \frac{1}{4} ln ∣ cos (2 x) ∣ + C

Solution steps

\int \frac{tan ( x )}{1 - tan ^{2} ( x )} d x

Rewrite using trig identities

= \int \frac{sin ( x ) cos ( x )}{cos ^{2} ( x ) - sin ^{2} ( x )} d x

Apply Integration By Parts

= x cos (x) sin (x) sec (2 x) - \int x sec^{2} (2 x) d x

\int x sec^{2} (2 x) d x = \frac{1}{2} x tan (2 x) + \frac{1}{4} ln ∣ cos (2 x) ∣

= x cos (x) sin (x) sec (2 x) - (\frac{1}{2} x tan (2 x) + \frac{1}{4} ln ∣ cos (2 x) ∣)

Simplify

= x cos (x) sin (x) sec (2 x) - \frac{1}{2} x tan (2 x) - \frac{1}{4} ln ∣ cos (2 x) ∣

Add a constant to the solution

= x cos (x) sin (x) sec (2 x) - \frac{1}{2} x tan (2 x) - \frac{1}{4} ln ∣ cos (2 x) ∣ + C

What is the integral of (tan(x))/(1-tan^2(x)) ?
The integral of (tan(x))/(1-tan^2(x)) is xcos(x)sin(x)sec(2x)-1/2 xtan(2x)-1/4 ln|cos(2x)|+C