What is the integral of e^{(x^2)^{22}}x^2)^2 ?

The integral of e^{(x^2)^{22}}x^2)^2 is x^{16}e^{x^{176}}+C

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integral of e^{(x^2)^{22}}x^2)^2

\int e^{(((x^{2})^{2})^{2})^{22}} d (((x^{2})^{2})^{2})^{2}

x^{16} e^{x^{176}} + C

Solution steps

\int e^{(((x^{2})^{2})^{2})^{22}} d (((x^{2})^{2})^{2})^{2}

Integral of a constant:

\int a d x = a x

= e^{(((x^{2})^{2})^{2})^{22}} (((x^{2})^{2})^{2})^{2}

Simplify

e^{(((x^{2})^{2})^{2})^{22}} (((x^{2})^{2})^{2})^{2} : x^{16} e^{x^{176}}

= x^{16} e^{x^{176}}

Add a constant to the solution

= x^{16} e^{x^{176}} + C

What is the integral of e^{(x^2)^{22}}x^2)^2 ?
The integral of e^{(x^2)^{22}}x^2)^2 is x^{16}e^{x^{176}}+C