What is the integral of (cos(pi/(x^{27)}))/(x^{28)} ?

The integral of (cos(pi/(x^{27)}))/(x^{28)} is -1/(27pi)sin(pi/(x^{27)})+C

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integral of (cos(pi/(x^{27)}))/(x^{28)}

\int \frac{cos ( \frac{π}{x ^{27}} )}{x ^{28}} d x

- \frac{1}{27 π} sin (\frac{π}{x ^{27}}) + C

Solution steps

\int \frac{cos ( \frac{π}{x ^{27}} )}{x ^{28}} d x

Apply u-substitution

= \int \frac{cos ( \frac{π}{u} )}{27 u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{27} \cdot \int \frac{cos ( \frac{π}{u} )}{u ^{2}} d u

Apply u-substitution

= \frac{1}{27} \cdot \int - \frac{cos ( v )}{π} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{27} (- \frac{1}{π} \cdot \int cos (v) d v)

Use the common integral:

\int cos (v) d v = sin (v)

= \frac{1}{27} (- \frac{1}{π} sin (v))

Substitute back

= \frac{1}{27} (- \frac{1}{π} sin (\frac{π}{x ^{27}}))

Simplify

\frac{1}{27} (- \frac{1}{π} sin (\frac{π}{x ^{27}})) : - \frac{1}{27 π} sin (\frac{π}{x ^{27}})

= - \frac{1}{27 π} sin (\frac{π}{x ^{27}})

Add a constant to the solution

= - \frac{1}{27 π} sin (\frac{π}{x ^{27}}) + C

What is the integral of (cos(pi/(x^{27)}))/(x^{28)} ?
The integral of (cos(pi/(x^{27)}))/(x^{28)} is -1/(27pi)sin(pi/(x^{27)})+C