What is the integral of 6a^{3x} ?

The integral of 6a^{3x} is (2a^{3x})/(ln(a))+C

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integral of 6a^{3x}

\int 6 a^{3 x} d x

\frac{2 a ^{3 x}}{ln ( a )} + C

Solution steps

\int 6 a^{3 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int a^{3 x} d x

Apply u-substitution

= 6 \cdot \int a^{u} \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \frac{1}{3} \cdot \int a^{u} d u

\int a^{x} d x = \frac{a ^{x}}{ln a}

= 6 \cdot \frac{1}{3} \cdot \frac{a ^{u}}{ln ( a )}

Substitute back

u = 3 x

= 6 \cdot \frac{1}{3} \cdot \frac{a ^{3 x}}{ln ( a )}

Simplify

6 \cdot \frac{1}{3} \cdot \frac{a ^{3 x}}{ln ( a )} : \frac{2 a ^{3 x}}{ln ( a )}

= \frac{2 a ^{3 x}}{ln ( a )}

Add a constant to the solution

= \frac{2 a ^{3 x}}{ln ( a )} + C

What is the integral of 6a^{3x} ?
The integral of 6a^{3x} is (2a^{3x})/(ln(a))+C