What is the integral of 1/(sin^2(x)) ?

The integral of 1/(sin^2(x)) is -cot(x)+C

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integral of 1/(sin^2(x))

integral

\frac{1}{sin ^{2} ( x )}

- cot (x) + C

Solution steps

\int \frac{1}{sin ^{2} ( x )} d x

Use the common integral:

\int \frac{1}{sin ^{2} ( x )} d x = - cot (x)

= - cot (x)

Add a constant to the solution

= - cot (x) + C

What is the integral of 1/(sin^2(x)) ?
The integral of 1/(sin^2(x)) is -cot(x)+C