What is the integral of (2x^3-5x^2-3x+4) ?

The integral of (2x^3-5x^2-3x+4) is (x^4)/2-(5x^3)/3-(3x^2)/2+4x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (2x^3-5x^2-3x+4)

\int (2 x^{3} - 5 x^{2} - 3 x + 4) d x

\frac{x ^{4}}{2} - \frac{5 x ^{3}}{3} - \frac{3 x ^{2}}{2} + 4 x + C

Solution steps

\int 2 x^{3} - 5 x^{2} - 3 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{3} d x - \int 5 x^{2} d x - \int 3 x d x + \int 4 d x

\int 2 x^{3} d x = \frac{x ^{4}}{2}

\int 5 x^{2} d x = \frac{5 x ^{3}}{3}

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 4 d x = 4 x

= \frac{x ^{4}}{2} - \frac{5 x ^{3}}{3} - \frac{3 x ^{2}}{2} + 4 x

Add a constant to the solution

= \frac{x ^{4}}{2} - \frac{5 x ^{3}}{3} - \frac{3 x ^{2}}{2} + 4 x + C

What is the integral of (2x^3-5x^2-3x+4) ?
The integral of (2x^3-5x^2-3x+4) is (x^4)/2-(5x^3)/3-(3x^2)/2+4x+C