What is the integral of (2x^2)/(sqrt(x^3-1)) ?

The integral of (2x^2)/(sqrt(x^3-1)) is 4/3 sqrt(x^3-1)+C

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integral of (2x^2)/(sqrt(x^3-1))

\int \frac{2 x ^{2}}{x ^{3} - 1} d x

\frac{4}{3} x^{3} - 1 + C

Solution steps

\int \frac{2 x ^{2}}{x ^{3} - 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{x ^{2}}{x ^{3} - 1} d x

Apply u-substitution

= 2 \cdot \int \frac{1}{3 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{3} \cdot \int \frac{1}{u} d u

Apply the Power Rule

= 2 \cdot \frac{1}{3} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = x^{3} - 1

= 2 \cdot \frac{1}{3} \cdot 2 (x^{3} - 1)^{\frac{1}{2}}

Simplify

2 \cdot \frac{1}{3} \cdot 2 (x^{3} - 1)^{\frac{1}{2}} : \frac{4}{3} x^{3} - 1

= \frac{4}{3} x^{3} - 1

Add a constant to the solution

= \frac{4}{3} x^{3} - 1 + C

What is the integral of (2x^2)/(sqrt(x^3-1)) ?
The integral of (2x^2)/(sqrt(x^3-1)) is 4/3 sqrt(x^3-1)+C