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Popular Calculus >

integral of (4x-1)

Solution

\int (4 x - 1) d x

Solution

2 x^{2} - x + C

Solution steps

\int 4 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x d x - \int 1 d x

\int 4 x d x = 2 x^{2}

\int 1 d x = x

= 2 x^{2} - x

Add a constant to the solution

= 2 x^{2} - x + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of (4x-1) ?
The integral of (4x-1) is 2x^2-x+C