What is the integral of 10xln(x) ?

The integral of 10xln(x) is 10(1/2 x^2ln(x)-(x^2)/4)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 10xln(x)

\int 10 x ln (x) d x

10 (\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4}) + C

Solution steps

\int 10 x ln (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int x ln (x) d x

Apply Integration By Parts

= 10 (\frac{1}{2} x^{2} ln (x) - \int \frac{x}{2} d x)

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= 10 (\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4})

Add a constant to the solution

= 10 (\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4}) + C

What is the integral of 10xln(x) ?
The integral of 10xln(x) is 10(1/2 x^2ln(x)-(x^2)/4)+C