What is the integral of (1+ln(x))/((xln(x^2))) ?

The integral of (1+ln(x))/((xln(x^2))) is 1/2 ln(2|ln(x)|)+1/2 ln(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (1+ln(x))/((xln(x^2)))

\int \frac{1 + ln ( x )}{( x ln ( x ^{2} ) )} d x

\frac{1}{2} ln (2 ∣ ln (x) ∣) + \frac{1}{2} ln (x) + C

Solution steps

\int \frac{1 + ln ( x )}{x ln ( x ^{2} )} d x

Expand

\frac{1 + ln ( x )}{x ln ( x ^{2} )} : \frac{1}{x ln ( x ^{2} )} + \frac{ln ( x )}{x ln ( x ^{2} )}

= \int \frac{1}{x ln ( x ^{2} )} + \frac{ln ( x )}{x ln ( x ^{2} )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x ln ( x ^{2} )} d x + \int \frac{ln ( x )}{x ln ( x ^{2} )} d x

\int \frac{1}{x ln ( x ^{2} )} d x = \frac{1}{2} ln (2 ∣ ln (x) ∣)

\int \frac{ln ( x )}{x ln ( x ^{2} )} d x = \frac{1}{2} ln (x)

= \frac{1}{2} ln (2 ∣ ln (x) ∣) + \frac{1}{2} ln (x)

Add a constant to the solution

= \frac{1}{2} ln (2 ∣ ln (x) ∣) + \frac{1}{2} ln (x) + C

What is the integral of (1+ln(x))/((xln(x^2))) ?
The integral of (1+ln(x))/((xln(x^2))) is 1/2 ln(2|ln(x)|)+1/2 ln(x)+C