What is the integral of-6cos(x)-4sin(x)-4 ?

The integral of-6cos(x)-4sin(x)-4 is -6sin(x)+4cos(x)-4x+C

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integral of-6cos(x)-4sin(x)-4

\int - 6 cos (x) - 4 sin (x) - 4 d x

- 6 sin (x) + 4 cos (x) - 4 x + C

Solution steps

\int - 6 cos (x) - 4 sin (x) - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 6 cos (x) d x - \int 4 sin (x) d x - \int 4 d x

\int 6 cos (x) d x = 6 sin (x)

\int 4 sin (x) d x = - 4 cos (x)

\int 4 d x = 4 x

= - 6 sin (x) - (- 4 cos (x)) - 4 x

Simplify

= - 6 sin (x) + 4 cos (x) - 4 x

Add a constant to the solution

= - 6 sin (x) + 4 cos (x) - 4 x + C

What is the integral of-6cos(x)-4sin(x)-4 ?
The integral of-6cos(x)-4sin(x)-4 is -6sin(x)+4cos(x)-4x+C