What is the integral of x^3+8sqrt(x) ?

The integral of x^3+8sqrt(x) is (x^4)/4+16/3 x^{3/2}+C

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integral of x^3+8sqrt(x)

\int x^{3} + 8 x d x

\frac{x ^{4}}{4} + \frac{16}{3} x^{\frac{3}{2}} + C

Solution steps

\int x^{3} + 8 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x + \int 8 x d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 8 x d x = \frac{16}{3} x^{\frac{3}{2}}

= \frac{x ^{4}}{4} + \frac{16}{3} x^{\frac{3}{2}}

Add a constant to the solution

= \frac{x ^{4}}{4} + \frac{16}{3} x^{\frac{3}{2}} + C

What is the integral of x^3+8sqrt(x) ?
The integral of x^3+8sqrt(x) is (x^4)/4+16/3 x^{3/2}+C