What is the integral of 1/500 e^{-x/(500)} ?

The integral of 1/500 e^{-x/(500)} is -e^{-x/(500)}+C

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integral of 1/500 e^{-x/(500)}

\int \frac{1}{500} e^{- \frac{x}{500}} d x

- e^{- \frac{x}{500}} + C

Solution steps

\int \frac{1}{500} e^{- \frac{x}{500}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{500} \cdot \int e^{- \frac{x}{500}} d x

Apply u-substitution

= \frac{1}{500} \cdot \int - 500 e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{500} (- 500 \cdot \int e^{u} d u)

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{500} (- 500 e^{u})

Substitute back

u = - \frac{x}{500}

= \frac{1}{500} (- 500 e^{- \frac{x}{500}})

Simplify

\frac{1}{500} (- 500 e^{- \frac{x}{500}}) : - e^{- \frac{x}{500}}

= - e^{- \frac{x}{500}}

Add a constant to the solution

= - e^{- \frac{x}{500}} + C

What is the integral of 1/500 e^{-x/(500)} ?
The integral of 1/500 e^{-x/(500)} is -e^{-x/(500)}+C