What is the integral of ((3x^2+2))/(x^2) ?

The integral of ((3x^2+2))/(x^2) is -(3x^2+2)/x+6x+C

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integral of ((3x^2+2))/(x^2)

\int \frac{( 3 x ^{2} + 2 )}{x ^{2}} d x

- \frac{3 x ^{2} + 2}{x} + 6 x + C

Solution steps

\int \frac{3 x ^{2} + 2}{x ^{2}} d x

Apply Integration By Parts

= - \frac{3 x ^{2} + 2}{x} - \int - 6 d x

\int - 6 d x = - 6 x

= - \frac{3 x ^{2} + 2}{x} - (- 6 x)

Simplify

= - \frac{3 x ^{2} + 2}{x} + 6 x

Add a constant to the solution

= - \frac{3 x ^{2} + 2}{x} + 6 x + C

What is the integral of ((3x^2+2))/(x^2) ?
The integral of ((3x^2+2))/(x^2) is -(3x^2+2)/x+6x+C