What is the integral of ((\sqrt[3]{t})^2-2) ?

The integral of ((\sqrt[3]{t})^2-2) is 3/5 t^{5/3}-2t+C

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integral of ((\sqrt[3]{t})^2-2)

\frac{3}{5} t^{\frac{5}{3}} - 2 t + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 2 d t = 2 t

= \frac{3}{5} t^{\frac{5}{3}} - 2 t

Add a constant to the solution

= \frac{3}{5} t^{\frac{5}{3}} - 2 t + C

What is the integral of ((\sqrt[3]{t})^2-2) ?
The integral of ((\sqrt[3]{t})^2-2) is 3/5 t^{5/3}-2t+C