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Popular Calculus >

integral of 8e^{4x}-1

Solution

\int 8 e^{4 x} - 1 d x

Solution

2 e^{4 x} - x + C

Solution steps

\int 8 e^{4 x} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 e^{4 x} d x - \int 1 d x

\int 8 e^{4 x} d x = 2 e^{4 x}

\int 1 d x = x

= 2 e^{4 x} - x

Add a constant to the solution

= 2 e^{4 x} - x + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of 8e^{4x}-1 ?
The integral of 8e^{4x}-1 is 2e^{4x}-x+C