What is the integral of (sec^2(2x)) ?

The integral of (sec^2(2x)) is 1/2 tan(2x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (sec^2(2x))

\int (sec^{2} (2 x)) d x

\frac{1}{2} tan (2 x) + C

Solution steps

\int sec^{2} (2 x) d x

Apply u-substitution

= \int sec^{2} (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= \frac{1}{2} tan (u)

Substitute back

u = 2 x

= \frac{1}{2} tan (2 x)

Add a constant to the solution

= \frac{1}{2} tan (2 x) + C

What is the integral of (sec^2(2x)) ?
The integral of (sec^2(2x)) is 1/2 tan(2x)+C