What is the integral of 3\sqrt[5]{x^2}+3 ?

The integral of 3\sqrt[5]{x^2}+3 is 15/7 x^{7/5}+3x+C

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integral of 3\sqrt[5]{x^2}+3

\frac{15}{7} x^{\frac{7}{5}} + 3 x + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 3 d x = 3 x

= \frac{15}{7} x^{\frac{7}{5}} + 3 x

Add a constant to the solution

= \frac{15}{7} x^{\frac{7}{5}} + 3 x + C

What is the integral of 3\sqrt[5]{x^2}+3 ?
The integral of 3\sqrt[5]{x^2}+3 is 15/7 x^{7/5}+3x+C