What is the integral of (3x^2)/(1-2x^3) ?

The integral of (3x^2)/(1-2x^3) is -1/2 ln|1-2x^3|+C

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integral of (3x^2)/(1-2x^3)

\int \frac{3 x ^{2}}{1 - 2 x ^{3}} d x

- \frac{1}{2} ln 1 - 2 x^{3} + C

Solution steps

\int \frac{3 x ^{2}}{1 - 2 x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{x ^{2}}{1 - 2 x ^{3}} d x

Apply u-substitution

= 3 \cdot \int - \frac{1}{6 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 (- \frac{1}{6} \cdot \int \frac{1}{u} d u)

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 3 (- \frac{1}{6} ln ∣ u ∣)

Substitute back

u = 1 - 2 x^{3}

= 3 (- \frac{1}{6} ln 1 - 2 x^{3})

Simplify

3 (- \frac{1}{6} ln 1 - 2 x^{3}) : - \frac{1}{2} ln 1 - 2 x^{3}

= - \frac{1}{2} ln 1 - 2 x^{3}

Add a constant to the solution

= - \frac{1}{2} ln 1 - 2 x^{3} + C

What is the integral of (3x^2)/(1-2x^3) ?
The integral of (3x^2)/(1-2x^3) is -1/2 ln|1-2x^3|+C