What is the integral of ((x^2)/4)^2 ?

The integral of ((x^2)/4)^2 is (x^5)/(16)-(x^5)/(20)+C

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integral of ((x^2)/4)^2

\int (\frac{x ^{2}}{4})^{2} d x

\frac{x ^{5}}{16} - \frac{x ^{5}}{20} + C

Solution steps

\int (\frac{x ^{2}}{4})^{2} d x

Apply Integration By Parts

= \frac{x ^{5}}{16} - \int \frac{x ^{4}}{4} d x

\int \frac{x ^{4}}{4} d x = \frac{x ^{5}}{20}

= \frac{x ^{5}}{16} - \frac{x ^{5}}{20}

Add a constant to the solution

= \frac{x ^{5}}{16} - \frac{x ^{5}}{20} + C

What is the integral of ((x^2)/4)^2 ?
The integral of ((x^2)/4)^2 is (x^5)/(16)-(x^5)/(20)+C