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Popular Calculus >

integral of-2x^2+8

Solution

\int - 2 x^{2} + 8 d x

Solution

- \frac{2 x ^{3}}{3} + 8 x + C

Solution steps

\int - 2 x^{2} + 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 2 x^{2} d x + \int 8 d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 8 d x = 8 x

= - \frac{2 x ^{3}}{3} + 8 x

Add a constant to the solution

= - \frac{2 x ^{3}}{3} + 8 x + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of-2x^2+8 ?
The integral of-2x^2+8 is -(2x^3)/3+8x+C