What is the integral of ((e^{2x}))/(1+e^x) ?

The integral of ((e^{2x}))/(1+e^x) is 1+e^x-ln|1+e^x|+C

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integral of ((e^{2x}))/(1+e^x)

\int \frac{( e ^{2 x} )}{1 + e ^{x}} d x

1 + e^{x} - ln ∣ 1 + e^{x} ∣ + C

Solution steps

\int \frac{e ^{2 x}}{1 + e ^{x}} d x

Apply u-substitution

= \int \frac{u - 1}{u} d u

Expand

\frac{u - 1}{u} : 1 - \frac{1}{u}

= \int 1 - \frac{1}{u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d u - \int \frac{1}{u} d u

\int 1 d u = u

\int \frac{1}{u} d u = ln ∣ u ∣

= u - ln ∣ u ∣

Substitute back

u = 1 + e^{x}

= 1 + e^{x} - ln ∣ 1 + e^{x} ∣

Add a constant to the solution

= 1 + e^{x} - ln ∣ 1 + e^{x} ∣ + C

What is the integral of ((e^{2x}))/(1+e^x) ?
The integral of ((e^{2x}))/(1+e^x) is 1+e^x-ln|1+e^x|+C