What is the integral of \sqrt[4]{16}cos(x) ?

The integral of \sqrt[4]{16}cos(x) is 2sin(x)+C

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integral of \sqrt[4]{16}cos(x)

2 sin (x) + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 2 sin (x)

Add a constant to the solution

= 2 sin (x) + C

What is the integral of \sqrt[4]{16}cos(x) ?
The integral of \sqrt[4]{16}cos(x) is 2sin(x)+C