What is the integral of 2/((x-3)^4) ?

The integral of 2/((x-3)^4) is -2/(3(x-3)^3)+C

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integral of 2/((x-3)^4)

\int \frac{2}{( x - 3 ) ^{4}} d x

- \frac{2}{3 ( x - 3 ) ^{3}} + C

Solution steps

\int \frac{2}{( x - 3 ) ^{4}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{( x - 3 ) ^{4}} d x

Apply u-substitution

= 2 \cdot \int \frac{1}{u ^{4}} d u

Apply the Power Rule

= 2 (- \frac{1}{3 u ^{3}})

Substitute back

u = x - 3

= 2 (- \frac{1}{3 ( x - 3 ) ^{3}})

Simplify

2 (- \frac{1}{3 ( x - 3 ) ^{3}}) : - \frac{2}{3 ( x - 3 ) ^{3}}

= - \frac{2}{3 ( x - 3 ) ^{3}}

Add a constant to the solution

= - \frac{2}{3 ( x - 3 ) ^{3}} + C

\int \frac{2}{4 - x ^{2}} d x

\int ln (p) d p

\int - 12 d x

\int 2 x^{2} - 2 x - 4 d x

\int \frac{2}{x + 7} d x

What is the integral of 2/((x-3)^4) ?
The integral of 2/((x-3)^4) is -2/(3(x-3)^3)+C