What is the integral of (sqrt(2)-sqrt(x))^2 ?

The integral of (sqrt(2)-sqrt(x))^2 is 2x-(4sqrt(2))/3 x^{3/2}+(x^2)/2+C

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integral of (sqrt(2)-sqrt(x))^2

\int (2 - x)^{2} d x

2 x - \frac{4 2}{3} x^{\frac{3}{2}} + \frac{x ^{2}}{2} + C

Solution steps

\int (2 - x)^{2} d x

Expand

(2 - x)^{2} : 2 - 2^{\frac{3}{2}} x + x

= \int 2 - 2^{\frac{3}{2}} x + x d x

2^{\frac{3}{2}} = 22

= \int 2 - 22 x + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 d x - \int 22 x d x + \int x d x

\int 2 d x = 2 x

\int 22 x d x = \frac{4 2}{3} x^{\frac{3}{2}}

\int x d x = \frac{x ^{2}}{2}

= 2 x - \frac{4 2}{3} x^{\frac{3}{2}} + \frac{x ^{2}}{2}

Add a constant to the solution

= 2 x - \frac{4 2}{3} x^{\frac{3}{2}} + \frac{x ^{2}}{2} + C

What is the integral of (sqrt(2)-sqrt(x))^2 ?
The integral of (sqrt(2)-sqrt(x))^2 is 2x-(4sqrt(2))/3 x^{3/2}+(x^2)/2+C