What is the integral of 10cos^2((5x)/2) ?

The integral of 10cos^2((5x)/2) is 5x+sin(5x)+C

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integral of 10cos^2((5x)/2)

\int 10 cos^{2} (\frac{5 x}{2}) d x

5 x + sin (5 x) + C

Solution steps

\int 10 cos^{2} (\frac{5 x}{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int cos^{2} (\frac{5 x}{2}) d x

Rewrite using trig identities

= 10 \cdot \int 1 - sin^{2} (\frac{5 x}{2}) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 10 (\int 1 d x - \int sin^{2} (\frac{5 x}{2}) d x)

\int 1 d x = x

\int sin^{2} (\frac{5 x}{2}) d x = \frac{1}{2} (x - \frac{1}{5} sin (5 x))

= 10 (x - \frac{1}{2} (x - \frac{1}{5} sin (5 x)))

Simplify

10 (x - \frac{1}{2} (x - \frac{1}{5} sin (5 x))) : 5 x + sin (5 x)

= 5 x + sin (5 x)

Add a constant to the solution

= 5 x + sin (5 x) + C

What is the integral of 10cos^2((5x)/2) ?
The integral of 10cos^2((5x)/2) is 5x+sin(5x)+C