What is the integral of ((x^3+x))/((x-1)) ?

The integral of ((x^3+x))/((x-1)) is (x^3)/3+(x^2)/2+2x+2ln|x-1|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of ((x^3+x))/((x-1))

\int \frac{( x ^{3} + x )}{( x - 1 )} d x

\frac{x ^{3}}{3} + \frac{x ^{2}}{2} + 2 x + 2 ln ∣ x - 1 ∣ + C

Solution steps

\int \frac{x ^{3} + x}{x - 1} d x

Long division

\frac{x ^{3} + x}{x - 1} : x^{2} + x + 2 + \frac{2}{x - 1}

= \int x^{2} + x + 2 + \frac{2}{x - 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int x d x + \int 2 d x + \int \frac{2}{x - 1} d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int x d x = \frac{x ^{2}}{2}

\int 2 d x = 2 x

\int \frac{2}{x - 1} d x = 2 ln ∣ x - 1 ∣

= \frac{x ^{3}}{3} + \frac{x ^{2}}{2} + 2 x + 2 ln ∣ x - 1 ∣

Add a constant to the solution

= \frac{x ^{3}}{3} + \frac{x ^{2}}{2} + 2 x + 2 ln ∣ x - 1 ∣ + C

What is the integral of ((x^3+x))/((x-1)) ?
The integral of ((x^3+x))/((x-1)) is (x^3)/3+(x^2)/2+2x+2ln|x-1|+C