What is the integral of (3x^{-2}-4x^{-3}) ?

The integral of (3x^{-2}-4x^{-3}) is -3/x+2/(x^2)+C

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integral of (3x^{-2}-4x^{-3})

\int (3 x^{- 2} - 4 x^{- 3}) d x

- \frac{3}{x} + \frac{2}{x ^{2}} + C

Solution steps

\int 3 x^{- 2} - 4 x^{- 3} d x

Simplify

3 x^{- 2} - 4 x^{- 3} : \frac{3}{x ^{2}} - \frac{4}{x ^{3}}

= \int \frac{3}{x ^{2}} - \frac{4}{x ^{3}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3}{x ^{2}} d x - \int \frac{4}{x ^{3}} d x

\int \frac{3}{x ^{2}} d x = - \frac{3}{x}

\int \frac{4}{x ^{3}} d x = - \frac{2}{x ^{2}}

= - \frac{3}{x} - (- \frac{2}{x ^{2}})

Simplify

= - \frac{3}{x} + \frac{2}{x ^{2}}

Add a constant to the solution

= - \frac{3}{x} + \frac{2}{x ^{2}} + C

What is the integral of (3x^{-2}-4x^{-3}) ?
The integral of (3x^{-2}-4x^{-3}) is -3/x+2/(x^2)+C