What is the integral of sec^2(x)cot^2(x) ?

The integral of sec^2(x)cot^2(x) is -cot(x)+C

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integral of sec^2(x)cot^2(x)

\int sec^{2} (x) cot^{2} (x) d x

- cot (x) + C

Solution steps

\int sec^{2} (x) cot^{2} (x) d x

Simplify

sec^{2} (x) cot^{2} (x) : csc^{2} (x)

= \int csc^{2} (x) d x

Use the common integral:

\int csc^{2} (x) d x = - cot (x)

= - cot (x)

Add a constant to the solution

= - cot (x) + C

What is the integral of sec^2(x)cot^2(x) ?
The integral of sec^2(x)cot^2(x) is -cot(x)+C