What is the integral of (x^7-3x)/(x^6) ?

The integral of (x^7-3x)/(x^6) is (x^2)/2+3/(4x^4)+C

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integral of (x^7-3x)/(x^6)

\int \frac{x ^{7} - 3 x}{x ^{6}} d x

\frac{x ^{2}}{2} + \frac{3}{4 x ^{4}} + C

Solution steps

\int \frac{x ^{7} - 3 x}{x ^{6}} d x

Expand

\frac{x ^{7} - 3 x}{x ^{6}} : x - \frac{3}{x ^{5}}

= \int x - \frac{3}{x ^{5}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x - \int \frac{3}{x ^{5}} d x

\int x d x = \frac{x ^{2}}{2}

\int \frac{3}{x ^{5}} d x = - \frac{3}{4 x ^{4}}

= \frac{x ^{2}}{2} - (- \frac{3}{4 x ^{4}})

Simplify

= \frac{x ^{2}}{2} + \frac{3}{4 x ^{4}}

Add a constant to the solution

= \frac{x ^{2}}{2} + \frac{3}{4 x ^{4}} + C

What is the integral of (x^7-3x)/(x^6) ?
The integral of (x^7-3x)/(x^6) is (x^2)/2+3/(4x^4)+C