What is the integral of (x+2)/((x-2)^4) ?

The integral of (x+2)/((x-2)^4) is -1/(2(x-2)^2)-4/(3(x-2)^3)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (x+2)/((x-2)^4)

\int \frac{x + 2}{( x - 2 ) ^{4}} d x

- \frac{1}{2 ( x - 2 ) ^{2}} - \frac{4}{3 ( x - 2 ) ^{3}} + C

Solution steps

\int \frac{x + 2}{( x - 2 ) ^{4}} d x

Expand

\frac{x + 2}{( x - 2 ) ^{4}} : \frac{x}{( x - 2 ) ^{4}} + \frac{2}{( x - 2 ) ^{4}}

= \int \frac{x}{( x - 2 ) ^{4}} + \frac{2}{( x - 2 ) ^{4}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{( x - 2 ) ^{4}} d x + \int \frac{2}{( x - 2 ) ^{4}} d x

\int \frac{x}{( x - 2 ) ^{4}} d x = - \frac{1}{2 ( x - 2 ) ^{2}} - \frac{2}{3 ( x - 2 ) ^{3}}

\int \frac{2}{( x - 2 ) ^{4}} d x = - \frac{2}{3 ( x - 2 ) ^{3}}

= - \frac{1}{2 ( x - 2 ) ^{2}} - \frac{2}{3 ( x - 2 ) ^{3}} - \frac{2}{3 ( x - 2 ) ^{3}}

Simplify

- \frac{1}{2 ( x - 2 ) ^{2}} - \frac{2}{3 ( x - 2 ) ^{3}} - \frac{2}{3 ( x - 2 ) ^{3}} : - \frac{1}{2 ( x - 2 ) ^{2}} - \frac{4}{3 ( x - 2 ) ^{3}}

= - \frac{1}{2 ( x - 2 ) ^{2}} - \frac{4}{3 ( x - 2 ) ^{3}}

Add a constant to the solution

= - \frac{1}{2 ( x - 2 ) ^{2}} - \frac{4}{3 ( x - 2 ) ^{3}} + C

What is the integral of (x+2)/((x-2)^4) ?
The integral of (x+2)/((x-2)^4) is -1/(2(x-2)^2)-4/(3(x-2)^3)+C