What is the integral of ln^2(y) ?

The integral of ln^2(y) is yln^2(y)-2(yln(y)-y)+C

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integral of ln^2(y)

\int ln^{2} (y) d y

y ln^{2} (y) - 2 (y ln (y) - y) + C

Solution steps

\int ln^{2} (y) d y

Apply Integration By Parts

= y ln^{2} (y) - \int 2 ln (y) d y

\int 2 ln (y) d y = 2 (y ln (y) - y)

= y ln^{2} (y) - 2 (y ln (y) - y)

Add a constant to the solution

= y ln^{2} (y) - 2 (y ln (y) - y) + C

What is the integral of ln^2(y) ?
The integral of ln^2(y) is yln^2(y)-2(yln(y)-y)+C