What is the integral of 2/(x^2+2x+3) ?

The integral of 2/(x^2+2x+3) is sqrt(2)arctan(1/(sqrt(2))(x+1))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 2/(x^2+2x+3)

\int \frac{2}{x ^{2} + 2 x + 3} d x

2 arctan (\frac{1}{2} (x + 1)) + C

Solution steps

\int \frac{2}{x ^{2} + 2 x + 3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{x ^{2} + 2 x + 3} d x

Complete the square

x^{2} + 2 x + 3 : (x + 1)^{2} + 2

= 2 \cdot \int \frac{1}{( x + 1 ) ^{2} + 2} d x

Apply u-substitution

= 2 \cdot \int \frac{1}{u ^{2} + 2} d u

Apply Integral Substitution

= 2 \cdot \int \frac{1}{2 ( v ^{2} + 1 )} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int \frac{1}{v ^{2} + 1} d v

Use the common integral:

\int \frac{1}{v ^{2} + 1} d v = arctan (v)

= 2 \cdot \frac{1}{2} arctan (v)

Substitute back

= 2 \cdot \frac{1}{2} arctan (\frac{x + 1}{2})

Simplify

2 \cdot \frac{1}{2} arctan (\frac{x + 1}{2}) : 2 arctan (\frac{1}{2} (x + 1))

= 2 arctan (\frac{1}{2} (x + 1))

Add a constant to the solution

= 2 arctan (\frac{1}{2} (x + 1)) + C

What is the integral of 2/(x^2+2x+3) ?
The integral of 2/(x^2+2x+3) is sqrt(2)arctan(1/(sqrt(2))(x+1))+C