What is the integral of sec^2(θ)e^{3tan(θ)} ?

The integral of sec^2(θ)e^{3tan(θ)} is 1/3 e^{3tan(θ)}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of sec^2(θ)e^{3tan(θ)}

\int sec^{2} (θ) e^{3 t a n (θ)} d θ

\frac{1}{3} e^{3 t a n (θ)} + C

Solution steps

\int sec^{2} (θ) e^{3 t a n (θ)} d θ

Apply u-substitution

= \int e^{3 u} d u

Apply u-substitution

= \int e^{v} \frac{1}{3} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int e^{v} d v

Use the common integral:

\int e^{v} d v = e^{v}

= \frac{1}{3} e^{v}

Substitute back

= \frac{1}{3} e^{3 t a n (θ)}

Add a constant to the solution

= \frac{1}{3} e^{3 t a n (θ)} + C

What is the integral of sec^2(θ)e^{3tan(θ)} ?
The integral of sec^2(θ)e^{3tan(θ)} is 1/3 e^{3tan(θ)}+C