What is the integral of (5x)/(x^2+3) ?

The integral of (5x)/(x^2+3) is 5/2 ln|x^2+3|+C

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integral of (5x)/(x^2+3)

\int \frac{5 x}{x ^{2} + 3} d x

\frac{5}{2} ln x^{2} + 3 + C

Solution steps

\int \frac{5 x}{x ^{2} + 3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int \frac{x}{x ^{2} + 3} d x

Apply u-substitution

= 5 \cdot \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 5 \cdot \frac{1}{2} ln ∣ u ∣

Substitute back

u = x^{2} + 3

= 5 \cdot \frac{1}{2} ln x^{2} + 3

Simplify

5 \cdot \frac{1}{2} ln x^{2} + 3 : \frac{5}{2} ln x^{2} + 3

= \frac{5}{2} ln x^{2} + 3

Add a constant to the solution

= \frac{5}{2} ln x^{2} + 3 + C

What is the integral of (5x)/(x^2+3) ?
The integral of (5x)/(x^2+3) is 5/2 ln|x^2+3|+C