What is the integral of 1/(x^2+3x+5) ?

The integral of 1/(x^2+3x+5) is 2/(sqrt(11))arctan((2x+3)/(sqrt(11)))+C

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integral of 1/(x^2+3x+5)

\int \frac{1}{x ^{2} + 3 x + 5} d x

\frac{2}{11} arctan (\frac{2 x + 3}{11}) + C

Solution steps

\int \frac{1}{x ^{2} + 3 x + 5} d x

Complete the square

x^{2} + 3 x + 5 : (x + \frac{3}{2})^{2} + \frac{11}{4}

= \int \frac{1}{( x + \frac{3}{2} ) ^{2} + \frac{11}{4}} d x

Apply u-substitution

= \int \frac{4}{4 u ^{2} + 11} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{4 u ^{2} + 11} d u

Apply Integral Substitution

= 4 \cdot \int \frac{1}{2 11 ( v ^{2} + 1 )} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{2 11} \cdot \int \frac{1}{v ^{2} + 1} d v

Use the common integral:

\int \frac{1}{v ^{2} + 1} d v = arctan (v)

= 4 \cdot \frac{1}{2 11} arctan (v)

Substitute back

= 4 \cdot \frac{1}{2 11} arctan (\frac{2}{11} (x + \frac{3}{2}))

Simplify

4 \cdot \frac{1}{2 11} arctan (\frac{2}{11} (x + \frac{3}{2})) : \frac{2}{11} arctan (\frac{2 x + 3}{11})

= \frac{2}{11} arctan (\frac{2 x + 3}{11})

Add a constant to the solution

= \frac{2}{11} arctan (\frac{2 x + 3}{11}) + C

What is the integral of 1/(x^2+3x+5) ?
The integral of 1/(x^2+3x+5) is 2/(sqrt(11))arctan((2x+3)/(sqrt(11)))+C