What is the integral of cos(24x) ?

The integral of cos(24x) is 1/24 sin(24x)+C

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integral of cos(24x)

\int cos (24 x) d x

\frac{1}{24} sin (24 x) + C

Solution steps

\int cos (24 x) d x

Apply u-substitution

= \int cos (u) \frac{1}{24} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{24} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{24} sin (u)

Substitute back

u = 24 x

= \frac{1}{24} sin (24 x)

Add a constant to the solution

= \frac{1}{24} sin (24 x) + C