What is the integral of (ln(y))/(y^2) ?

The integral of (ln(y))/(y^2) is -(ln(y))/y-1/y+C

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integral of (ln(y))/(y^2)

\int \frac{ln ( y )}{y ^{2}} d y

- \frac{ln ( y )}{y} - \frac{1}{y} + C

Solution steps

\int \frac{ln ( y )}{y ^{2}} d y

Apply Integration By Parts

= - \frac{ln ( y )}{y} - \int - \frac{1}{y ^{2}} d y

\int - \frac{1}{y ^{2}} d y = \frac{1}{y}

= - \frac{ln ( y )}{y} - \frac{1}{y}

Add a constant to the solution

= - \frac{ln ( y )}{y} - \frac{1}{y} + C

What is the integral of (ln(y))/(y^2) ?
The integral of (ln(y))/(y^2) is -(ln(y))/y-1/y+C