What is the integral of ((log_{10}(x)))/x ?

The integral of ((log_{10}(x)))/x is log_{10}(x)ln|x|-(ln|x|^2)/(2ln(10))+C

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integral of ((log_{10}(x)))/x

\int \frac{( lo g _{10} ( x ) )}{x} d x

lo g_{10} (x) ln ∣ x ∣ - \frac{ln ∣ x ∣ ^{2}}{2 ln ( 10 )} + C

Solution steps

\int \frac{lo g _{10} ( x )}{x} d x

Apply Integration By Parts

= lo g_{10} (x) ln ∣ x ∣ - \int \frac{ln ∣ x ∣}{ln ( 10 ) x} d x

\int \frac{ln ∣ x ∣}{ln ( 10 ) x} d x = \frac{ln ∣ x ∣ ^{2}}{2 ln ( 10 )}

= lo g_{10} (x) ln ∣ x ∣ - \frac{ln ∣ x ∣ ^{2}}{2 ln ( 10 )}

Add a constant to the solution

= lo g_{10} (x) ln ∣ x ∣ - \frac{ln ∣ x ∣ ^{2}}{2 ln ( 10 )} + C

What is the integral of ((log_{10}(x)))/x ?
The integral of ((log_{10}(x)))/x is log_{10}(x)ln|x|-(ln|x|^2)/(2ln(10))+C