What is the integral of e^xsin(pix) ?

The integral of e^xsin(pix) is -(pie^xcos(pix))/(pi^2+1)+(e^xsin(pix))/(pi^2+1)+C

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integral of e^xsin(pix)

\int e^{x} sin (π x) d x

- \frac{π e ^{x} cos ( π x )}{π ^{2} + 1} + \frac{e ^{x} sin ( π x )}{π ^{2} + 1} + C

Solution steps

\int e^{x} sin (π x) d x

Apply Integration By Parts

= - \frac{1}{π} e^{x} cos (π x) - \int - \frac{1}{π} e^{x} cos (π x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{π} e^{x} cos (π x) - (- \frac{1}{π} \cdot \int e^{x} cos (π x) d x)

Apply Integration By Parts

= - \frac{1}{π} e^{x} cos (π x) - (- \frac{1}{π} (e^{x} \frac{1}{π} sin (π x) - \int e^{x} \frac{1}{π} sin (π x) d x))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{π} e^{x} cos (π x) - (- \frac{1}{π} (e^{x} \frac{1}{π} sin (π x) - \frac{1}{π} \cdot \int e^{x} sin (π x) d x))

Therefore

\int e^{x} sin (π x) d x = - \frac{1}{π} e^{x} cos (π x) - (- \frac{1}{π} (e^{x} \frac{1}{π} sin (π x) - \frac{1}{π} \cdot \int e^{x} sin (π x) d x))

Isolate

\int e^{x} sin (π x) d x

= - \frac{π e ^{x} cos ( π x )}{π ^{2} + 1} + \frac{e ^{x} sin ( π x )}{π ^{2} + 1}

Add a constant to the solution

= - \frac{π e ^{x} cos ( π x )}{π ^{2} + 1} + \frac{e ^{x} sin ( π x )}{π ^{2} + 1} + C

What is the integral of e^xsin(pix) ?
The integral of e^xsin(pix) is -(pie^xcos(pix))/(pi^2+1)+(e^xsin(pix))/(pi^2+1)+C