What is the integral of e^x+12x^2-4 ?

The integral of e^x+12x^2-4 is e^x+4x^3-4x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of e^x+12x^2-4

\int e^{x} + 12 x^{2} - 4 d x

e^{x} + 4 x^{3} - 4 x + C

Solution steps

\int e^{x} + 12 x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{x} d x + \int 12 x^{2} d x - \int 4 d x

\int e^{x} d x = e^{x}

\int 12 x^{2} d x = 4 x^{3}

\int 4 d x = 4 x

= e^{x} + 4 x^{3} - 4 x

Add a constant to the solution

= e^{x} + 4 x^{3} - 4 x + C

What is the integral of e^x+12x^2-4 ?
The integral of e^x+12x^2-4 is e^x+4x^3-4x+C