What is the integral of x/((7+5x^2)^{3/2)} ?

The integral of x/((7+5x^2)^{3/2)} is -1/(5(5x^2+7)^{1/2)}+C

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integral of x/((7+5x^2)^{3/2)}

\int \frac{x}{( 7 + 5 x ^{2} ) ^{\frac{3}{2}}} d x

- \frac{1}{5 ( 5 x ^{2} + 7 ) ^{\frac{1}{2}}} + C

Solution steps

\int \frac{x}{( 7 + 5 x ^{2} ) ^{\frac{3}{2}}} d x

Apply u-substitution

= \int \frac{1}{10 u ^{\frac{3}{2}}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{10} \cdot \int \frac{1}{u ^{\frac{3}{2}}} d u

Apply the Power Rule

= \frac{1}{10} (- \frac{2}{u ^{\frac{1}{2}}})

Substitute back

u = 7 + 5 x^{2}

= \frac{1}{10} (- \frac{2}{( 7 + 5 x ^{2} ) ^{\frac{1}{2}}})

Simplify

\frac{1}{10} (- \frac{2}{( 7 + 5 x ^{2} ) ^{\frac{1}{2}}}) : - \frac{1}{5 ( 5 x ^{2} + 7 ) ^{\frac{1}{2}}}

= - \frac{1}{5 ( 5 x ^{2} + 7 ) ^{\frac{1}{2}}}

Add a constant to the solution

= - \frac{1}{5 ( 5 x ^{2} + 7 ) ^{\frac{1}{2}}} + C

What is the integral of x/((7+5x^2)^{3/2)} ?
The integral of x/((7+5x^2)^{3/2)} is -1/(5(5x^2+7)^{1/2)}+C