What is the integral of (x+1)/(sqrt(2x-1)) ?

The integral of (x+1)/(sqrt(2x-1)) is 1/3 (x+1)sqrt(2x-1)+sqrt(2x-1)+C

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integral of (x+1)/(sqrt(2x-1))

\int \frac{x + 1}{2 x - 1} d x

\frac{1}{3} (x + 1) 2 x - 1 + 2 x - 1 + C

Solution steps

\int \frac{x + 1}{2 x - 1} d x

Apply u-substitution

= \int \frac{u ^{2} + 1}{2} + 1 d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{u ^{2} + 1}{2} d u + \int 1 d u

\int \frac{u ^{2} + 1}{2} d u = \frac{1}{2} (\frac{u ^{3}}{3} + u)

\int 1 d u = u

= \frac{1}{2} (\frac{u ^{3}}{3} + u) + u

Substitute back

u = 2 x - 1

= \frac{1}{2} (\frac{( 2 x - 1 ) ^{3}}{3} + 2 x - 1) + 2 x - 1

Simplify

\frac{1}{2} (\frac{( 2 x - 1 ) ^{3}}{3} + 2 x - 1) + 2 x - 1 : \frac{1}{3} (x + 1) 2 x - 1 + 2 x - 1

= \frac{1}{3} (x + 1) 2 x - 1 + 2 x - 1

Add a constant to the solution

= \frac{1}{3} (x + 1) 2 x - 1 + 2 x - 1 + C

What is the integral of (x+1)/(sqrt(2x-1)) ?
The integral of (x+1)/(sqrt(2x-1)) is 1/3 (x+1)sqrt(2x-1)+sqrt(2x-1)+C