What is the integral of-2+(t^2+3t)^{6/5}-t^3 ?

The integral of-2+(t^2+3t)^{6/5}-t^3 is ((t^2+3t)^{6/5}-2-t^3)x+C

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integral of-2+(t^2+3t)^{6/5}-t^3

\int - 2 + (t^{2} + 3 t)^{\frac{6}{5}} - t^{3} d x

((t^{2} + 3 t)^{\frac{6}{5}} - 2 - t^{3}) x + C

Solution steps

\int - 2 + (t^{2} + 3 t)^{\frac{6}{5}} - t^{3} d x

Integral of a constant:

\int a d x = a x

= ((t^{2} + 3 t)^{\frac{6}{5}} - 2 - t^{3}) x

Add a constant to the solution

= ((t^{2} + 3 t)^{\frac{6}{5}} - 2 - t^{3}) x + C

What is the integral of-2+(t^2+3t)^{6/5}-t^3 ?
The integral of-2+(t^2+3t)^{6/5}-t^3 is ((t^2+3t)^{6/5}-2-t^3)x+C