What is the integral of x(5x^2-9)^{3/2} ?

The integral of x(5x^2-9)^{3/2} is 1/25 (5x^2-9)^{5/2}+C

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integral of x(5x^2-9)^{3/2}

\int x (5 x^{2} - 9)^{\frac{3}{2}} d x

\frac{1}{25} (5 x^{2} - 9)^{\frac{5}{2}} + C

Solution steps

\int x (5 x^{2} - 9)^{\frac{3}{2}} d x

Apply u-substitution

= \int \frac{u ^{\frac{3}{2}}}{10} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{10} \cdot \int u^{\frac{3}{2}} d u

Apply the Power Rule

= \frac{1}{10} \cdot \frac{2}{5} u^{\frac{5}{2}}

Substitute back

u = 5 x^{2} - 9

= \frac{1}{10} \cdot \frac{2}{5} (5 x^{2} - 9)^{\frac{5}{2}}

Simplify

\frac{1}{10} \cdot \frac{2}{5} (5 x^{2} - 9)^{\frac{5}{2}} : \frac{1}{25} (5 x^{2} - 9)^{\frac{5}{2}}

= \frac{1}{25} (5 x^{2} - 9)^{\frac{5}{2}}

Add a constant to the solution

= \frac{1}{25} (5 x^{2} - 9)^{\frac{5}{2}} + C

What is the integral of x(5x^2-9)^{3/2} ?
The integral of x(5x^2-9)^{3/2} is 1/25 (5x^2-9)^{5/2}+C